five hundredths of millimeter - 0.05mm

The vernier scale is a technological device that increases the sensibility of a scale when subdivides its smaler division.

On this simulator the scale is 1:100, that means the graved numbers are the hundredth part of meter or the centimeter - bigger marks, that it was subdivided by ten -smaler marks, the millimeter. The vernier has twenty spaces between vertical marks, so, it divides by twenty the millimeter, the smaler division of the main scale, obtaining five hundredths of millimeter 0.05mm.

We recommend you to interact with the page: Virtual vernier scale - simulator of use and reading in decimal millimeter before you go on.

figure 1

measure with a scale provided of vernier with twenty divisions - increase of sensibilitty

How we saw on page Virtual vernier scale - simulator of use and reading in decimal millimeter , by definition **resolution is the smaller difference between indications of a display device that can the significatly perceived **.

On this simulator the smaller division of the main scale - fixed scale - is i millimeter, thta was divided by twenty divisions of vernier.

Resolution = 1mm / 20 = 0.05mm

The resolution of this simulator is five hundredths of millimeter 0.05mm.

## vernier scale in millimeter resolution five hundredths 0.05mm | reading | observation interpretation | ||
---|---|---|---|---|

main scale | vernier scale | |||

1cm = 10mm + mm | 20 divisions = 0.05mm | main scale + vernier scale | ||

0 * 10mm + 2 * 1mm = 2mm | 6 * 0.1mm + 1 * 0.05mm = 0.65mm | 2mm + 0.65mm = 2.65mm | The zero of vernier didn't get in the 1st big mark of scale and swept to the 2nd smaller mark. In the vernier the 6th big mark is close to aligment, but, who was aligned was the small mark | |

0 * 10mm + 4 * 1mm = 4mm | 0 * 0.1mm + 1 * 0.05mm = 0.05mm | 4mm + 0.05mm = 4.05mm | The zero of vernier didn't get in the 1st big mark of scale and swept to the 4th smaller mark. In the vernier the zero big mark is close to aligment, but, who was aligned was the small mark | |

1 * 10mm + 1 * 1mm = 11mm | 7 * 0.1mm + 1 * 0.05mm = 0.75mm | 11mm + 0.75mm = 11.75mm | The zero of vernier didn't get in the 1st big mark of scale and swept to the 1st smaller mark. In the vernier the 7th big mark is close to aligment, but, who was aligned was the small mark | |

3 * 10mm + 2 * 1mm = 32mm | 9 * 0.1mm + 1 * 0.05mm = 0.95mm | 32mm + 0.95mm = 32.95mm | The zero of vernier didn't get in the 3rd big mark of scale and swept to the 2nd smaller mark. In the vernier the 9th big mark is close to aligment, but, who was aligned was the small mark, and without caution, we could wrongly read 33.95mm Reading: 32.95mm | |

4 * 10mm + 1 * 1mm = 41mm | 4 * 0.1mm + 1 * 0.05mm = 0.45mm | 41mm + 0.4(8)mm = 41.4(8)mm | The zero of vernier didn't get in the 4th big mark of scale and swept to the 1st smaller mark. In the vernier the 4th big mark sweeps, so, as teh smaller mark, with no aligment of the 5th big mark, I interpretated that it was beyond of the hald part of the way (0.08mm) | |

the value between (8) was obtained by interpolationo | The resolution of monitor it may not allow that the marks align perfectlly, to solve this we added a small red circle |

See other examples of commented exercises of vernier and resolution 0.05mm